Find the zeros of the following quadratic pol | vedclass

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(B) To find the zeros of the quadratic polynomial $p(x) = 15x^2 + 16x + 4$,we set $p(x) = 0$.$15x^2 + 16x + 4 = 0$We split the middle term $16x$ into

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$-\frac{2}{3}, -\frac{2}{5}$

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(B) To find the zeros of the quadratic polynomial $p(x) = 15x^2 + 16x + 4$,we set $p(x) = 0$.$15x^2 + 16x + 4 = 0$We split the middle term $16x$ into two parts such that their sum is $16x$ and their product is $15 	imes 4 = 60x^2$. The factors are $10x$ and $6x$.$15x^2 + 10x + 6x + 4 = 0$$5x(3x + 2) + 2(3x + 2) = 0$$(5x + 2)(3x + 2) = 0$Setting each factor to zero:$5x + 2 = 0 \implies x = -\frac{2}{5}$$3x + 2 = 0 \implies x = -\frac{2}{3}$Thus,the zeros are $-\frac{2}{3}$ and $-\frac{2}{5}$.

Find the zeros of the following quadratic polynomial: $15x^2 + 16x + 4$.

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